y^2+3=2(y-2)

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Solution for y^2+3=2(y-2) equation:


Simplifying
y2 + 3 = 2(y + -2)

Reorder the terms:
3 + y2 = 2(y + -2)

Reorder the terms:
3 + y2 = 2(-2 + y)
3 + y2 = (-2 * 2 + y * 2)
3 + y2 = (-4 + 2y)

Solving
3 + y2 = -4 + 2y

Solving for variable 'y'.

Reorder the terms:
3 + 4 + -2y + y2 = -4 + 2y + 4 + -2y

Combine like terms: 3 + 4 = 7
7 + -2y + y2 = -4 + 2y + 4 + -2y

Reorder the terms:
7 + -2y + y2 = -4 + 4 + 2y + -2y

Combine like terms: -4 + 4 = 0
7 + -2y + y2 = 0 + 2y + -2y
7 + -2y + y2 = 2y + -2y

Combine like terms: 2y + -2y = 0
7 + -2y + y2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-7' to each side of the equation.
7 + -2y + -7 + y2 = 0 + -7

Reorder the terms:
7 + -7 + -2y + y2 = 0 + -7

Combine like terms: 7 + -7 = 0
0 + -2y + y2 = 0 + -7
-2y + y2 = 0 + -7

Combine like terms: 0 + -7 = -7
-2y + y2 = -7

The y term is -2y.  Take half its coefficient (-1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
-2y + 1 + y2 = -7 + 1

Reorder the terms:
1 + -2y + y2 = -7 + 1

Combine like terms: -7 + 1 = -6
1 + -2y + y2 = -6

Factor a perfect square on the left side:
(y + -1)(y + -1) = -6

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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